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internal/atlas: Better pixel allocations

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Updates #1681
Updates #1788
This commit is contained in:
Hajime Hoshi 2021-08-26 03:35:18 +09:00
parent 40d2dd3ba7
commit 91a7288027
1 changed files with 25 additions and 1 deletions
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26
internal/atlas/image.go
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@ -55,6 +55,8 @@ func temporaryPixelsByteSize(size int) int {
return l
}
// alloc allocates the pixels and reutrns it.
// Be careful that the returned pixels might not be zero-cleared.
func (t *temporaryPixels) alloc(size int) []byte {
if len(t.pixels) < t.pos+size {
t.pixels = make([]byte, temporaryPixelsByteSize(t.pos+size))
@ -79,8 +81,11 @@ func (t *temporaryPixels) resetAtFrameEnd() {
// Let the pixels GCed if this is not used for a while.
if t.notFullyUsedTime == maxNotFullyUsedTime && len(t.pixels) > 0 {
t.pixels = nil
t.pos = 0
}
// Reset the position and reuse the allocated bytes.
// t.pixels should already be sent to GPU, then this can be reused.
t.pos = 0
}
func max(a, b int) int {
@ -533,6 +538,25 @@ func (i *Image) replacePixels(pix []byte) {
pixb := theTemporaryPixels.alloc(4 * w * h)
// Clear the edges. pixb might not be zero-cleared.
rowPixels := 4 * w
for i := 0; i < rowPixels; i++ {
pixb[i] = 0
}
for j := 1; j < h-1; j++ {
pixb[rowPixels*j] = 0
pixb[rowPixels*j+1] = 0
pixb[rowPixels*j+2] = 0
pixb[rowPixels*j+3] = 0
pixb[rowPixels*(j+1)-4] = 0
pixb[rowPixels*(j+1)-3] = 0
pixb[rowPixels*(j+1)-2] = 0
pixb[rowPixels*(j+1)-1] = 0
}
for i := 0; i < rowPixels; i++ {
pixb[rowPixels*(h-1)+i] = 0
}
// Copy the content.
for j := 0; j < oh; j++ {
copy(pixb[4*((j+paddingSize)*w+paddingSize):], pix[4*j*ow:4*(j+1)*ow])